I NEED VECTOR HELP!!! CAN ANYONE HERE DO CAL 2 CALCULATIONS???

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I NEED VECTOR HELP!!! CAN ANYONE HERE DO CAL 2 CALCULATIONS???

Mathematics
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Find two unit vectors that make an angle of 60° with v = ‹6, 8›. Give your answers correct to three decimal places.
ANYONE????
I tried, sitting this one out. Will be watching with great interest.

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Other answers:

ROACHIE sorry :(
:P
ill give you a medal if someone figures this out...lol
ah!
what is the magnitude of u?
|v|=10
6a + 8b = \[\left| u \right|\] (10)(1/2)
... u?
by theorem 3 we need u * v = \[\left| v \right| \left| u \right|\] cos 60
would u be 1?
\[\sqrt{a ^{2}+b^{2}}\]
if i knew what the magnitude of u was i could figure this problem out.
oh, u=<6,8>??
right?
u =
v = <6,8>
the magnitude of u (unit vector) is 1 i dont remember the formula for that theorem you were referring
yea, I dont know where u came from but yes, u being a unit vector has magnitude 1
6a + 8b = 5 therefore b=5/8 - 3/4a
a^2 + (5/8 -3/4a)^2 = 1
?? any thoughts on that?
where does the 5 come from?
1/2 (10)
u * v = |v||u| cos 60 now I see u, duh
why are we dividing 10 (|v|) by 2
cos of 60 is 1/2
someone want to factor that out for me...
because im sure to f THAT up.
if we know that u is a unit vector then v * u = |v|cos 60 if you unit vector v then v*u = cos 60 that how I think of it...
im not following r . . . . .
haha...25/64 -30/32a +9/16a^2
v-hat = v/|v|
then quadratic... fun fun
|v-hat|=1
30/32 +- \[\sqrt{30/32^{2}-4(25/64)(9/16)}/2(25/64)\]
fml
did you add the original a^2 to the factor? dumbcow?
no i didn;t multiply everything by 64 100a^2 -60a -39 = 0 a = -.3928, .9928
then i need to plug those back into 5/8 -3/4a to find b right?
yep
<-.3928,.9196> and <.9928, -.1196>
looks good
YES!!!!!
thank god!

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