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anonymous
 4 years ago
A polynomial with a degree of 3 that when divided by x+2 has a remainder of 4
anonymous
 4 years ago
A polynomial with a degree of 3 that when divided by x+2 has a remainder of 4

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mathmate
 4 years ago
Best ResponseYou've already chosen the best response.2P(x)=(x3)(xp)(xq)4 where p,q are any integers (or even real numbers)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0can you write it in a different way; X^33^24

mathmate
 4 years ago
Best ResponseYou've already chosen the best response.2Choose values of p and q then expand. Do not forget to add the term "4".

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok thank you. But I never seen a problem written like that. I dont know how to solve it.

mathmate
 4 years ago
Best ResponseYou've already chosen the best response.2Sorry, the above equation I gave for P(x) is wrong. I took the wrong number. The factor (divisor) should be (x+2), so the revised P(x) is then: P(x)=(x+2)(xp)(xq)4 you still get to choose integers p and q. Since (x+2) divides (x+2)(xp)(xq) exactly, the remainder is zero for any choice of p and q. By adding on 4, we make sure the remainder is 4 as required.
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