A polynomial with a degree of 3 that when divided by x+2 has a remainder of -4
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where p,q are any integers (or even real numbers)
can you write it in a different way; X^3-3^2-4
Choose values of p and q then expand.
Do not forget to add the term "-4".
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ok thank you. But I never seen a problem written like that. I dont know how to solve it.
Sorry, the above equation I gave for P(x) is wrong. I took the wrong number. The factor (divisor) should be (x+2), so the revised P(x) is then:
you still get to choose integers p and q.
Since (x+2) divides (x+2)(x-p)(x-q) exactly, the remainder is zero for any choice of p and q.
By adding on -4, we make sure the remainder is -4 as required.