A polynomial with a degree of 3 that when divided by x+2 has a remainder of -4

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A polynomial with a degree of 3 that when divided by x+2 has a remainder of -4

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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P(x)=(x-3)(x-p)(x-q)-4 where p,q are any integers (or even real numbers)
can you write it in a different way; X^3-3^2-4
Choose values of p and q then expand. Do not forget to add the term "-4".

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ok thank you. But I never seen a problem written like that. I dont know how to solve it.
Sorry, the above equation I gave for P(x) is wrong. I took the wrong number. The factor (divisor) should be (x+2), so the revised P(x) is then: P(x)=(x+2)(x-p)(x-q)-4 you still get to choose integers p and q. Since (x+2) divides (x+2)(x-p)(x-q) exactly, the remainder is zero for any choice of p and q. By adding on -4, we make sure the remainder is -4 as required.
ok thank you
You're welcome! :)

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