anonymous
  • anonymous
A polynomial with a degree of 3 that when divided by x+2 has a remainder of -4
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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mathmate
  • mathmate
P(x)=(x-3)(x-p)(x-q)-4 where p,q are any integers (or even real numbers)
anonymous
  • anonymous
can you write it in a different way; X^3-3^2-4
mathmate
  • mathmate
Choose values of p and q then expand. Do not forget to add the term "-4".

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anonymous
  • anonymous
ok thank you. But I never seen a problem written like that. I dont know how to solve it.
mathmate
  • mathmate
Sorry, the above equation I gave for P(x) is wrong. I took the wrong number. The factor (divisor) should be (x+2), so the revised P(x) is then: P(x)=(x+2)(x-p)(x-q)-4 you still get to choose integers p and q. Since (x+2) divides (x+2)(x-p)(x-q) exactly, the remainder is zero for any choice of p and q. By adding on -4, we make sure the remainder is -4 as required.
anonymous
  • anonymous
ok thank you
mathmate
  • mathmate
You're welcome! :)

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