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What happens after this..? use separation of variables to solve the initial value problem

Mathematics
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Forgot the parenthesis: e^( (x^2/2) + 2x + c)
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sub youe initial values and solve for C y= C(e^( .5x^2 + 2x ))- 5 for x = 0, y = 1 1 = C - 5 C = 6 so y= 6e^( .5x^2 + 2x )- 5

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Other answers:

ln(6)=c
How did you bring C out?
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e^C = C its math magic
? Huh? But for example, e^(2) does not equal to 2...
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e^c = 6
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cinar!
yes!
ahh I see now! Thank you very much
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just try to have fun with it.

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