anonymous
  • anonymous
What happens after this..? use separation of variables to solve the initial value problem
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
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anonymous
  • anonymous
Forgot the parenthesis: e^( (x^2/2) + 2x + c)
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anonymous
  • anonymous
sub youe initial values and solve for C y= C(e^( .5x^2 + 2x ))- 5 for x = 0, y = 1 1 = C - 5 C = 6 so y= 6e^( .5x^2 + 2x )- 5

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anonymous
  • anonymous
ln(6)=c
anonymous
  • anonymous
How did you bring C out?
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anonymous
  • anonymous
e^C = C its math magic
anonymous
  • anonymous
? Huh? But for example, e^(2) does not equal to 2...
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anonymous
  • anonymous
|dw:1327563797536:dw|
anonymous
  • anonymous
e^c = 6
anonymous
  • anonymous
|dw:1327563871600:dw|
anonymous
  • anonymous
cinar!
anonymous
  • anonymous
yes!
anonymous
  • anonymous
ahh I see now! Thank you very much
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anonymous
  • anonymous
just try to have fun with it.

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