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Denebel
 4 years ago
What happens after this..?
use separation of variables to solve the initial value problem
Denebel
 4 years ago
What happens after this..? use separation of variables to solve the initial value problem

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Denebel
 4 years ago
Best ResponseYou've already chosen the best response.0Forgot the parenthesis: e^( (x^2/2) + 2x + c)

Roachie
 4 years ago
Best ResponseYou've already chosen the best response.0sub youe initial values and solve for C y= C(e^( .5x^2 + 2x )) 5 for x = 0, y = 1 1 = C  5 C = 6 so y= 6e^( .5x^2 + 2x ) 5

Denebel
 4 years ago
Best ResponseYou've already chosen the best response.0How did you bring C out?

Denebel
 4 years ago
Best ResponseYou've already chosen the best response.0? Huh? But for example, e^(2) does not equal to 2...

Denebel
 4 years ago
Best ResponseYou've already chosen the best response.0ahh I see now! Thank you very much

Roachie
 4 years ago
Best ResponseYou've already chosen the best response.0just try to have fun with it.
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