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Denebel
Group Title
What happens after this..?
use separation of variables to solve the initial value problem
 2 years ago
 2 years ago
Denebel Group Title
What happens after this..? use separation of variables to solve the initial value problem
 2 years ago
 2 years ago

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Denebel Group TitleBest ResponseYou've already chosen the best response.0
Forgot the parenthesis: e^( (x^2/2) + 2x + c)
 2 years ago

Roachie Group TitleBest ResponseYou've already chosen the best response.0
sub youe initial values and solve for C y= C(e^( .5x^2 + 2x )) 5 for x = 0, y = 1 1 = C  5 C = 6 so y= 6e^( .5x^2 + 2x ) 5
 2 years ago

Denebel Group TitleBest ResponseYou've already chosen the best response.0
How did you bring C out?
 2 years ago

Roachie Group TitleBest ResponseYou've already chosen the best response.0
e^C = C its math magic
 2 years ago

Denebel Group TitleBest ResponseYou've already chosen the best response.0
? Huh? But for example, e^(2) does not equal to 2...
 2 years ago

cinar Group TitleBest ResponseYou've already chosen the best response.2
dw:1327563797536:dw
 2 years ago

cinar Group TitleBest ResponseYou've already chosen the best response.2
dw:1327563871600:dw
 2 years ago

Denebel Group TitleBest ResponseYou've already chosen the best response.0
ahh I see now! Thank you very much
 2 years ago

Roachie Group TitleBest ResponseYou've already chosen the best response.0
just try to have fun with it.
 2 years ago
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