anonymous
  • anonymous
Iron is obtained commercially by the reaction of hematite (Fe2O3) with carbon monoxide. How many grams of iron are produced if 13.0 moles of hematite react with 38.0 moles of carbon monoxide?
Chemistry
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Xishem
  • Xishem
This is the equation for that reaction: \[Fe_2O_3(s)+3CO(g) \rightarrow 2Fe(s)+3CO_2(g)\]This is a limiting reactant problem, so let's first find what the limiting reactant is. For 13 mols of hematite, we need: \[13molFe_2O_3*\frac{3molCO}{1molFe_2O_3}=39molCO\]We only have 38.0 mols of CO, so that means that the CO is the limiting reactant. Now, let's see how much iron is produced by 38.0 mols of CO: \[38.0molCO*\frac{2.00molFe}{3.00molCO}=25.3molFe\]

Looking for something else?

Not the answer you are looking for? Search for more explanations.