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anonymous

  • 4 years ago

To win a prize at a carnival, a player must toss a beanbag onto a circular disk with a diameter of 8 inches. Suppose the carnival's organizer wants to reduce the chances players may win. He decides to reduce the area of the circular disk by half. What is the diameter of the new disk? A. 4√2 inches B. 4 inches C. 2√2 inches D. 2 inches

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  1. anonymous
    • 4 years ago
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    A

  2. anonymous
    • 4 years ago
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    A

  3. anonymous
    • 4 years ago
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    presently, the area is 64pi we want to halve this. THis would be 32pi. area of a circle is pi (radius)^2 radius^2=32 radius=sqrt32 4root2

  4. anonymous
    • 4 years ago
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    Oh okay thanks alexray19

  5. anonymous
    • 4 years ago
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    No wait, I did my algebra wrong...

  6. anonymous
    • 4 years ago
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    Really?

  7. anonymous
    • 4 years ago
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    its A

  8. anonymous
    • 4 years ago
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    Well I just did it myself, I'm sticking with A.

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spraguer (Moderator)
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