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anonymous

  • 4 years ago

How would you simplify (2x^2 - 9)?

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  1. anonymous
    • 4 years ago
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    (xsqrt2+3)(xsqrt2-3)

  2. anonymous
    • 4 years ago
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    (x^2 + 3) (x^2 - 3) but then you'd have x^4?

  3. anonymous
    • 4 years ago
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    |dw:1327557774107:dw|

  4. anonymous
    • 4 years ago
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    Because I have to find the 0s of a solution, and the original problem is 4x^4 - 18x^2 = 0 I took out 2x^2(2x^2-9)=0, then now I'm stuck..

  5. anonymous
    • 4 years ago
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    is there a certain way you need to solve it? Such as:factoring, quadratic formula, completing the square, etc. ?

  6. anonymous
    • 4 years ago
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    4x^2-9 (2sqrtx-3)(2sqrtx=3)

  7. anonymous
    • 4 years ago
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    there isn't any specified, they just want us to find the 0s, but with that Oindrilla, how would I find the 0s?

  8. anonymous
    • 4 years ago
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    |dw:1327558063247:dw|

  9. anonymous
    • 4 years ago
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    oh true sorry

  10. anonymous
    • 4 years ago
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    oh meant to right = instead of + by the way srry

  11. anonymous
    • 4 years ago
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    shinigami.. how does that work though? to find the 0s because I'd have to find the square of 2 wouldn't I?

  12. anonymous
    • 4 years ago
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    try the quadratic formula

  13. anonymous
    • 4 years ago
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    |dw:1327558211920:dw|

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spraguer (Moderator)
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