Mani_Jha
  • Mani_Jha
If I hang a small cylindrical object with a string, I get a pendulum. When I swing it, the object mostly rotates about its axis. What effect does this rotation have on the time period of the pendulum? Can we find out the effect quantitatively?
MIT 8.01 Physics I Classical Mechanics, Fall 1999
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
T = 2π*SQRT(L/g) so i dont think that the torque would poduce any effect on the time period as T is independent of mass(moment of inertia) in casev of rotating objects
anonymous
  • anonymous
post further questions in physics section as there are good answering people there
anonymous
  • anonymous
Interesting question, @Salini - That relation is only valid for point mass objects. This is a cylinder. Hence we have to consider it a torsional as well as physical pendulum according to the question. That's what you're asking right?

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Mani_Jha
  • Mani_Jha
yeah, that's right siddhantsharan. i want it for a sphere or cylinder or any rigid object
Mani_Jha
  • Mani_Jha
and there will be some effect, even if little. that i am certain, because while measuring the time period of a pendulum in the lab, we were asked to make sure that the bob doesnt rotate about its axis
anonymous
  • anonymous
Yes I think youre right. g eff. will decrease.
anonymous
  • anonymous
Sorry For Replying relli late.
anonymous
  • anonymous
And Even the Amplitude will decrease. Reason: Total Energy remains constant.
anonymous
  • anonymous
from the experiments using a simple pendulum i have noticed that as the pendulum starts to rotate slowly,the time of oscillations starts to decrease
Mani_Jha
  • Mani_Jha
@201116252, That's probably because the amplitude decreases. The pendulum should take less time to cover less distance.

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