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T = 2π*SQRT(L/g) so i dont think that the torque would poduce any effect on the time period as T is independent of mass(moment of inertia) in casev of rotating objects
post further questions in physics section as there are good answering people there
Interesting question, @Salini - That relation is only valid for point mass objects. This is a cylinder. Hence we have to consider it a torsional as well as physical pendulum according to the question. That's what you're asking right?
yeah, that's right siddhantsharan. i want it for a sphere or cylinder or any rigid object
and there will be some effect, even if little. that i am certain, because while measuring the time period of a pendulum in the lab, we were asked to make sure that the bob doesnt rotate about its axis
Yes I think youre right. g eff. will decrease.
Sorry For Replying relli late.
And Even the Amplitude will decrease. Reason: Total Energy remains constant.
from the experiments using a simple pendulum i have noticed that as the pendulum starts to rotate slowly,the time of oscillations starts to decrease