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Mani_Jha

  • 4 years ago

If I hang a small cylindrical object with a string, I get a pendulum. When I swing it, the object mostly rotates about its axis. What effect does this rotation have on the time period of the pendulum? Can we find out the effect quantitatively?

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  1. anonymous
    • 4 years ago
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    T = 2π*SQRT(L/g) so i dont think that the torque would poduce any effect on the time period as T is independent of mass(moment of inertia) in casev of rotating objects

  2. anonymous
    • 4 years ago
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    post further questions in physics section as there are good answering people there

  3. anonymous
    • 4 years ago
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    Interesting question, @Salini - That relation is only valid for point mass objects. This is a cylinder. Hence we have to consider it a torsional as well as physical pendulum according to the question. That's what you're asking right?

  4. Mani_Jha
    • 4 years ago
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    yeah, that's right siddhantsharan. i want it for a sphere or cylinder or any rigid object

  5. Mani_Jha
    • 4 years ago
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    and there will be some effect, even if little. that i am certain, because while measuring the time period of a pendulum in the lab, we were asked to make sure that the bob doesnt rotate about its axis

  6. anonymous
    • 4 years ago
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    Yes I think youre right. g eff. will decrease.

  7. anonymous
    • 4 years ago
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    Sorry For Replying relli late.

  8. anonymous
    • 4 years ago
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    And Even the Amplitude will decrease. Reason: Total Energy remains constant.

  9. anonymous
    • 4 years ago
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    from the experiments using a simple pendulum i have noticed that as the pendulum starts to rotate slowly,the time of oscillations starts to decrease

  10. Mani_Jha
    • 4 years ago
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    @201116252, That's probably because the amplitude decreases. The pendulum should take less time to cover less distance.

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