A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

anonymous

  • 4 years ago

You are designing a rectangular poster to contain 50 in^2 of printing with a 4 in. margin at the top and bottom and a 2 inch margin at each side. What overall dimensions will minimize the amount of paper used?

  • This Question is Closed
  1. anonymous
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    You have say length and width of the printable area as x and y respectively.. then xy = 50 .. Now you have total length and width (including margins) as (x + 2*4) and (y + 2*2) respectively. You need to minimize (x + 2*4)(50/x + 2*2). Differentiate this wrt x to get x = 10 and y = 5 ..

  2. anonymous
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    My textbook says 18 and 9.

  3. anonymous
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    dude I gave you the dimensions of the printing area ... now add 4*2 and 2*2 to the respective dimensions to get the net dimension = 18 and 9

  4. anonymous
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Ah, didn't read your reply completely. Thanks for the response.

  5. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.