anonymous
  • anonymous
a wooden block of mass 8 kg is tied to a string attatched to the bottom of the tank.In equilibrium the block is completely immersed in water. if relative density of wood is 0.8 and g=10m/s^2 then what is the value of tension in the string?
Physics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
\[F _{g}= Mg = 8kg x 10m/s² = 80N\] that is the gravitational force which pulling the block down. bouncy force = the total weight of water displaced by the block, since u say that the wooden block is totally immersed into the water, The volume of water displaced = the volume of wooden block. We need the volume of wooden block, but we only have density and mass. \[Density = m/v\] \[v = m \times v/m\] so with tat equation, u can cross the m and u will get the v, volume. \[v = m \times v/m\] \[m \div m/v = m \times v/m = v\] then v= 10, idk what is the unit since u didn't state the unite for the density. now, volume of water displaced also = 10 and i guess the density of water is 1.0 \[v \times m/v = m\] \[10 \times 1.0=10\] mass of water displaced. \[F _{bouyancy} = 10 \times 10 =100N\] resultant force on the string(tension), lets consider upward force is positve , negaative is for downward force, 100N-80N = 20N 20N of tension
anonymous
  • anonymous
as the relative density of wood is less than 1( relative density or water ), the water lifts the wooden block up to the surface. Hence there wont't be any tension in the string.
JamesJ
  • JamesJ
http://openstudy.com/users/sachin%20vishaul#/updates/4f1ec1f6e4b04992dd24cb4b From the last time we worked this problem, there are three forces acting on the block of wood F_g = force of gravity (down) F_b = force of buoyancy (up) F_s = force from the string (down) The block is in equilibrium hence the sum of the three is zero. Use that to solve for F_s. The magnitude of F_s is the tension in the string. We have found the mass of water displaced is 10 kg, hence \[ F_b = +10g \] On the other hand the weight of the block is \[ F_g = -8g \] As \[ F_b + F_g + F_s = 0 \] we have \[ F_s = -(F_b + F_g) = -(10g - 8g) = -2g = - 19.6 \ N \] This is a downward force and that makes complete intuitive sense. We know the block is less dense that the water so without the string it would rise to the top of the water.

Looking for something else?

Not the answer you are looking for? Search for more explanations.