## anonymous 4 years ago show steps please Solve the system by using elimination or elimination with multiplication. x - y = 3 and x + y = 7 Solve the system by using elimination or elimination with multiplication. 2x + 3y = 12 and 3x + 2y = 13

1. anonymous

x-y=3 x+y=7 Add them(elimination) 2x=10 x=5 x-y=3 y=2 (5,2)

2. anonymous

first u need to find the value of either x or y example: x - y = 3 and x + y = 7 x - y=3 x =3+y or y = x-3

3. anonymous

is (5,2) he anwser for the first one?

4. anonymous

yep!

5. anonymous

try to do the second one urself

6. anonymous

2x+3y=12 3x+2y=13 multiply the first one by -2. multiply the second one by 3. -4x-6y=-24 9x+6y=39 5x=15 x=3 Use this hint above if you need it :)

7. anonymous

3, 2?

8. anonymous

good!

9. anonymous

Solve the system by using elimination or elimination with multiplication. x + y = 16 and x + y = -2 is this one no solution?

10. anonymous

yeah

11. anonymous

3x - 2y = 9 and -3x + 2y = -9 and is this on no solution or infinte solutions??

12. anonymous

notice if you eliminate it, there's nothing left

13. anonymous

k thanks so much. thats what i thought. ya just making sure.

14. anonymous

the last one you asked is infinite

15. anonymous

they're the same thing

16. anonymous

ok good thats what i thought! not on hw they arent lol

17. anonymous

haha true :P

18. anonymous

$6\sqrt{2}-3\sqrt{2}$

19. anonymous

3 sqrt 2

20. anonymous

haha i already got it :p this one is hard. one sec.

21. anonymous

$5\sqrt{3}+8\sqrt{3}-6\sqrt{2}+4\sqrt{2}$

22. anonymous

13 sqrt3 -2 sqrt 2

23. anonymous

lol, is this school hw?

24. anonymous

ya

25. anonymous

how did you get that?

26. anonymous

$\sqrt{2 } =x$ $\sqrt{3} = y$ 5y+8y -6x+4x= 13y -2x and u will get : $13\sqrt{3}-2\sqrt{2}$

27. anonymous

that is the easier way to understand it