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anonymous

  • 4 years ago

show steps please Solve the system by using elimination or elimination with multiplication. x - y = 3 and x + y = 7 Solve the system by using elimination or elimination with multiplication. 2x + 3y = 12 and 3x + 2y = 13

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  1. anonymous
    • 4 years ago
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    x-y=3 x+y=7 Add them(elimination) 2x=10 x=5 x-y=3 y=2 (5,2)

  2. anonymous
    • 4 years ago
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    first u need to find the value of either x or y example: x - y = 3 and x + y = 7 x - y=3 x =3+y or y = x-3

  3. anonymous
    • 4 years ago
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    is (5,2) he anwser for the first one?

  4. anonymous
    • 4 years ago
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    yep!

  5. anonymous
    • 4 years ago
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    try to do the second one urself

  6. anonymous
    • 4 years ago
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    2x+3y=12 3x+2y=13 multiply the first one by -2. multiply the second one by 3. -4x-6y=-24 9x+6y=39 5x=15 x=3 Use this hint above if you need it :)

  7. anonymous
    • 4 years ago
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    3, 2?

  8. anonymous
    • 4 years ago
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    good!

  9. anonymous
    • 4 years ago
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    Solve the system by using elimination or elimination with multiplication. x + y = 16 and x + y = -2 is this one no solution?

  10. anonymous
    • 4 years ago
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    yeah

  11. anonymous
    • 4 years ago
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    3x - 2y = 9 and -3x + 2y = -9 and is this on no solution or infinte solutions??

  12. anonymous
    • 4 years ago
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    notice if you eliminate it, there's nothing left

  13. anonymous
    • 4 years ago
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    k thanks so much. thats what i thought. ya just making sure.

  14. anonymous
    • 4 years ago
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    the last one you asked is infinite

  15. anonymous
    • 4 years ago
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    they're the same thing

  16. anonymous
    • 4 years ago
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    ok good thats what i thought! not on hw they arent lol

  17. anonymous
    • 4 years ago
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    haha true :P

  18. anonymous
    • 4 years ago
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    \[6\sqrt{2}-3\sqrt{2}\]

  19. anonymous
    • 4 years ago
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    3 sqrt 2

  20. anonymous
    • 4 years ago
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    haha i already got it :p this one is hard. one sec.

  21. anonymous
    • 4 years ago
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    \[5\sqrt{3}+8\sqrt{3}-6\sqrt{2}+4\sqrt{2}\]

  22. anonymous
    • 4 years ago
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    13 sqrt3 -2 sqrt 2

  23. anonymous
    • 4 years ago
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    lol, is this school hw?

  24. anonymous
    • 4 years ago
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    ya

  25. anonymous
    • 4 years ago
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    how did you get that?

  26. anonymous
    • 4 years ago
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    \[\sqrt{2 } =x \] \[\sqrt{3} = y\] 5y+8y -6x+4x= 13y -2x and u will get : \[13\sqrt{3}-2\sqrt{2}\]

  27. anonymous
    • 4 years ago
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    that is the easier way to understand it

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