anonymous
  • anonymous
hey what is tan(45+a) equal to?
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
how does this (1 - tan^2a)/(1+tan^2a) cos 2a?
anonymous
  • anonymous
(1 - tan^2a)/(1+tan^2a) = cos 2a?
anonymous
  • anonymous
\[ \tan (a + b) = \frac{\tan a + \tan b}{1 - \tan a \tan b}\] Hmm that's the formula. One thing you can do is use this \(\large \tan a = \frac{\sin a}{\cos a}\) \[\frac{1 - \frac{\sin^2a}{\cos^2a}}{1 + \frac{\sin^2a}{\cos^2a}}\]I hope you can do the algebra from here.

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anonymous
  • anonymous
ishaan do we expand the 1 into sin^2a +cos^2a?
anonymous
  • anonymous
yeah! :-D
anonymous
  • anonymous
can you expand this out cause i don't really get it
anonymous
  • anonymous
okay, i will try. \[\large \frac{\frac{cos^2a - \sin^2a}{\cos^2a}}{\frac{\cos^2a+\sin^2a}{\cos^2a}}\] \[\Large \frac{\frac{cos^2a - \sin^2a}{\cancel\cos^2a}}{\frac{1}{\cancel \cos^2a}}\] \[\cos^2a - \sin^2a = \cos 2a\]
anonymous
  • anonymous
oh i see thank you very much
anonymous
  • anonymous
no problem
anonymous
  • anonymous
hey ishaan don't we get 2cos2a then and not 2/cos2a
anonymous
  • anonymous
no i think you forgot the real equation it's \(2 \frac{1 +tan^2a}{1 - tan^2a}\)

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