2x4+4x6+6x8.........to n terms..... how to get the 20th term of this sequence

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2x4+4x6+6x8.........to n terms..... how to get the 20th term of this sequence

Mathematics
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Un=4n^2+4n U20=4(20)^2+4(20) =1680
Un=4n(n+1)
how to reach that equation??

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Other answers:

8 24 48 ... 16 24 8 maybe, then we take the first diagonal and apply some pascal to it with any luck
When we do sequences(or series) we always need to take the term number into our thinking process. So, naturally, we look at the first term and say 2 times one is 2 so 2n is part of the equation somehow.
sry, i have a way of doing it, but its not that easy to explain...once you do lots of series and sequences, there tends to be a patter like usually n+1 or n+2 or 2n is involved. Just checks work with my method.
8*nC0+16*nC1+8*nC2 this is similar to what i recall; prolly needs to be refreshed to be accurate tho
8*1+16n+8n(n-1)/2 lets see if this is a good recollection lol 8 + 16n +4n^2-4n 4n^2 -12n +8 ?
when n=0, we get 8 when n=1 we get 0 ... doh!!
2,4,6 = 2+2(n-1) x 4,6,8 = 4+2(n-1) an = (2+2n-2) * (4+2n-2) a20 = (2+2(20)-2)*(4+2(20)-2) = (2(20))*(2+2(20)) = (40)*(42) = 1680 ?? yay, we match now
right,,,thanx mates

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