A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

anonymous

  • 4 years ago

if 1/(a+b) + 1/(c+b)=1/b........then prove a, b, c are in geometric progression

  • This Question is Closed
  1. anonymous
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    solve the equation by bringing all terms in numerator .. you would get ac + ab + bc+ b^2 = bc + b^2 + ab + b^2 simplify to get ac = b^2 hence proved

  2. anonymous
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    thanx mate'

  3. anonymous
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    a geometric progression, also known as a geometric sequence, is a sequence of numbers where each term after the first is found by multiplying the previous one by a fixed non-zero number called the common ratio. For satisfying G.P., three consecutive terms a ,b and c shall satisfy the following equation: b^2 = ac

  4. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.