A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
How do I solve this binomial (factoring) : x^8256x^4. Thank you :)
anonymous
 4 years ago
How do I solve this binomial (factoring) : x^8256x^4. Thank you :)

This Question is Closed

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.2First factor out the common factor which is x^4

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0x^4 *(x^2  16) *(x^2 + 16) = x^4 *(x4)(x+4)(x^2 + 16)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Is this the answer: x^4(x^2+16)?

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.2\[x ^{4}(x ^{4}16) = x ^{4}(x ^{2}4)(x ^{2}+4)=x ^{4}(x2)(x+2)(x ^{2}+4)\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Is a formula used to solve this?

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.2The difference of two squares.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0how did you get (x^2+4)

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.2Use it twice. Once on the x^416 and again on x^24

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.2\[x ^{4}16=(x ^{2}4)(x ^{2}+4)\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@Mertsj .. it should be (x4)(x+4) instead of (x2)(x+2) .. you have to factor 256 which is 16^2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0x^4  256 = (x  4)(x+4)(x^2 + 16)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dont you take x^2 out of x^4 Mertsj

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.2\[x ^{4}256=(x ^{2}16)(x ^{2}+16)=\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so wouldnt the final answer not have x^4, what is the forumula exactly?

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.2\[(x4)(x+4)(x ^{2}+16)\]

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.2Then put the x^4 that we factored out in the front of it.

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.2\[x ^{4}(x4)(x+4)(x ^{2}+16)\]

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.2That's the final answer.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0cant you break down the 16 tho?

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.2No. The sum of two squares is not factorable in the set of real numbers.

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.2The difference of two squares is factorable but not the sum.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Thanks want to help me with another? :)

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.2That is the sum of two squares and it cannot be factored.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0im going to start a new question, this time i want to check an answer i got :)
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.