anonymous
  • anonymous
the speed of a car increases from 10m/s to 20m/s with an acceleration of 3.0 m/s^2. Find the distance covered during the acceleration.
Physics
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
v^=u^2+2as 20x20=10x10+2x3xs s=distance covered 400=100+6s s=50meters
anonymous
  • anonymous
by 3rd eqn of motion
anonymous
  • anonymous
I got it now. thanks a lot :)

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

JamesJ
  • JamesJ
This is again conservation of energy. Work = (Force)x(distance) = Fs = mas But Work = Change in KE = (1/2)mv^2 - (1/2)mu^2 = (m/2)(v^2 - u^2) Hence mas = (m/2)(v^2 - u^2) or v^2 - u^2 = 2as

Looking for something else?

Not the answer you are looking for? Search for more explanations.