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b2) would be 12c5 - 9c5 .. total number of ways of selection - number of ways when he selects no book from the author ..
b) 1) 792
do u know how to do the rest? i mean c
okk c1) would be (26C2 - 26) * (899) * 26 C2) would be 9/899
_ _ _ _ _ _ first two spaces can be filled in 7*6 =42 ways the three no.s = 9*10*10=900 ways last letter =19 ways so total no. of combinations 42*900*19 2nd part all three no. same= 9*1*1=9 ways combinations with all three no.s same=42*9*19 probability= 9/900=1/100
don't you have answers??
What does between 100 and 899 means? Interval is closed or open?
how is 100 to 999- 899 no.s it's 900 no.s
ohh i didnt see the restriction on letters .. but the concept remains the same .. :)
guys im sorry i dont really understand this i havent taken it ever , i just want to teach it to someone, so if u can show me the way
I second ash's answer, it seems correct.
@shaan,>> c1) would be (26C2 - 26) * (899) * 26c1) would be (26C2 - 26) * (899) * 26 I still don't know why are you multiplying by 26 in the last case.
I messed it .. I didn't see that there were restrictions on number of letters (I assumed they were 26) ...
ah fine then :)
do the first two letters have to be different?
btw ash's answer assumes that the first two letter is different.
that is why i asked
can we make two assumptions? does it mean it has two answers?
Good point zarkon, it's not clear from the problem statement, however as this is PIN i have a feeling that it should be 7*7. Yes lala, answer would be different.
Thankyou guys you are all awesome !!!!!!