anonymous
  • anonymous
ABCD is a square where A is the point (0,2) and C is the point (8,4). AC and BD are diagonals of the square and they intersect at E. Find the coordinates of B and D.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
I have found out the coordinate of E which is(4,3) and the equation of Bd and length of AE
amistre64
  • amistre64
slope is 1/4?
amistre64
  • amistre64
so perp slope is -4

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anonymous
  • anonymous
the ans for the coordinate of B is(5,-1) & D is (3,7)
anonymous
  • anonymous
but i do not know how to derive at it
amistre64
  • amistre64
the slope form a to c aint 1 so its not a square that situated nicely like that is it?
amistre64
  • amistre64
slope from a to c is: 2/8 = 1/4
anonymous
  • anonymous
ABCD is a square in the question
amistre64
  • amistre64
e is a+c/2 for midpoint 8,4 0,2 ---- 8,6 /2 = 4,3 e is good
amistre64
  • amistre64
y=-4x+4(4)+3 y=-4x+19 is the equation of the line perp to ac and thru 4,3
amistre64
  • amistre64
hmmm, so. ; this laptop doesnt make this easier lol
amistre64
  • amistre64
we need a vector that is the length of ae
anonymous
  • anonymous
its \[\sqrt{17}\] length of ae
amistre64
  • amistre64
8,4 -4,3 ---- <4,1>; mag = sqrt(17) that ougt to be fun to play with
anonymous
  • anonymous
i cant find a way to find the coordinate through the length of ae LOL
amistre64
  • amistre64
so the vector representation of say eb is our -4/1 slope
amistre64
  • amistre64
<1,-4> is out vector ... duh lol
amistre64
  • amistre64
form e move 1,-4 and -1,4 to get to the other corners
anonymous
  • anonymous
i was tinking of finding the coordinate through the x-axis difference and y-axis difference but it doesnt seem to work
amistre64
  • amistre64
4,3 1,-4 ----- 5,-1 4,3 -1,4 ----- 3,7
anonymous
  • anonymous
i get it thx:) alot
amistre64
  • amistre64
took a bit my my brain clicked lol
Hero
  • Hero
So what were the correct points? For some reason, I'm getting (3,7) and (5,-1), but the question is which one is B and which one is D
anonymous
  • anonymous
Hi im very sorry could you explain what is a vector?
amistre64
  • amistre64
|dw:1327672189805:dw|
amistre64
  • amistre64
a vector can be represented as a directed line segment; something like an arrow with distance and direction defines a vector
anonymous
  • anonymous
how did u arrive at a vector of (-1,4)
amistre64
  • amistre64
|dw:1327672246456:dw|
amistre64
  • amistre64
the slope of a line IS its vector i took the slope of the line from A to C
amistre64
  • amistre64
not drawn correctly in this pic, but same concept nonetheless
anonymous
  • anonymous
gradient AC= 1/4 thus the vector is (-1,4 ) and gradient AB= 4 vector is (-4,1)?
amistre64
  • amistre64
the slope of the line from A to C is: C (8,4) -A (0,2) -------- 8, 2 ; slope = 2/8; 1/4 the vector from A to C is then <4 , 1>
amistre64
  • amistre64
a vector is notated the same as a point, except for the < > parts that indicate it as a vector. it is 4 wide and 1 tall; the components of its gradient (slope)
anonymous
  • anonymous
How did u get C (8,4) -A (0,2) -------- 8, 2
amistre64
  • amistre64
its called subtraction
amistre64
  • amistre64
8-0 , 4-2 these are the parts of the slope formula
amistre64
  • amistre64
its just easier for me to do them in this way then to try and sort out what goes where when its already done
amistre64
  • amistre64
but to be clear about the vector from A to C, I was a little off in my explaining. The vector from A to C is actually <8,2>; half of this is going to be to the midpoint of E, since a midpoint is in the middle <8,2> ------ = <4,1>, is our vector from A to E 2
anonymous
  • anonymous
i see thank you i will try to understand & do the question first, if I still do not understand could I still look for you? thx::)
amistre64
  • amistre64
i might be around; it might be better to repost a new question, or even this one again so that others have a better chance to see it up on the left and give their views as well :)

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