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anonymous

  • 4 years ago

How can i determe the value of k such that the system below does not have a unique solution:

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  1. anonymous
    • 4 years ago
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    |dw:1327597002487:dw|

  2. amistre64
    • 4 years ago
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    matrix it up

  3. anonymous
    • 4 years ago
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    okay i did that, but now i am stuck as to how to determine it

  4. amistre64
    • 4 years ago
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    im gonna wolf this for simplicity and see if it helps {1,1,k,3},{1,k,1,2},{k,1,1,1}

  5. anonymous
    • 4 years ago
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    right, thats what i have, i have no idea how to proceed

  6. amistre64
    • 4 years ago
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    now does it matter if its no or infinite solutions? just a s long as its not unique

  7. anonymous
    • 4 years ago
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    it just says, "does not have a unique solution"

  8. amistre64
    • 4 years ago
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    from the divisions i see that k not= 1 or -2

  9. anonymous
    • 4 years ago
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    how did they get those fractions

  10. amistre64
    • 4 years ago
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    they row reduced it

  11. amistre64
    • 4 years ago
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    rref form is the row reduced form using elementary matrix operations of row addition and such

  12. amistre64
    • 4 years ago
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    click on "show steps"

  13. amistre64
    • 4 years ago
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    11k 3 *-1 add to r2 -1-1 -k -3 1 k 1 2 ----------- 0 k-1 1-k -1 11k 3 *-k add to r3 -k -k -2k -3k k 1 1 1 ----------------- 0 1-k 1-2k 1-3k 1 1 k 3 0 k-1 1-k -1 0 1-k 1-2k 1-3k and so forth till you get a diagonal of 1s

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spraguer (Moderator)
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