anonymous
  • anonymous
The width of a rectangle is 7 less than twice its length. If the area of the rectangle is 113 cm^2, what is the length of the diagonal? i did x(2x-7)=113 did the quadformula and it didnt work :\
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
the quad formula will give you the length of the rectangle. from this you can get the width. Once you have the length and the width, you get the length of the diagonal by using the pythagorean theorem.
jhonyy9
  • jhonyy9
2x^2 -7x -113=0 x_1,_2=(7+/- sqrt(49+904))/4 =(7+/- sqrt953)/4 =
anonymous
  • anonymous
Yeah I did that but you end up getting decimals and it doesnt work in the hw site for some reason.... i got 9.47 for the length and 11.94 for the width based on the equation. Idk if I did something wrong

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anonymous
  • anonymous
hmm ill check your results
jhonyy9
  • jhonyy9
so if sqrt953 =30,8 -so continue from this
anonymous
  • anonymous
length is 9.47, width is 11.92. Length of the diagonal is 15.2
anonymous
  • anonymous
nope 15.2 doesnt work either :\
anonymous
  • anonymous
hmmm
anonymous
  • anonymous
stupid question but...it wants the length of the diagonal is cm, right?
anonymous
  • anonymous
in*
anonymous
  • anonymous
Yeah im assuming
anonymous
  • anonymous
it lists _____cm though
jhonyy9
  • jhonyy9
x=37,8/4 =9,4 w=2l-7=18,8-7=11,8 diagonal d=sqrt(139.24+88,36)=sqrt227,6 =15,08
anonymous
  • anonymous
not sure what the issue with your hw site is; make sure you carry all your digits forward prior to rounding and other than that, your correct
anonymous
  • anonymous
carrying all the digits worked thank you.
anonymous
  • anonymous
ok good.. :)

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