anonymous
  • anonymous
Apply Gauss's law to determine the electric intensity at a point due to the infinite sheet of charge?????
MIT 8.01 Physics I Classical Mechanics, Fall 1999
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
TuringTest
  • TuringTest
Not sure what you mean by electric intensity. Gauss's law gives the electric field easily enough: Consider a Gaussian pillbox shape|dw:1327733787509:dw|each oval shape is of area dA, and the arrows are in the direction of E and dA, which coincide.\[\frac q\epsilon_0=\oint\overrightarrow{E}\cdot\overrightarrow{dA}=2EA\]Noting that we can write charge as charge density (sigma) times area\[\frac{\sigma A}{\epsilon_0}=2EA\to E=\frac{\sigma}{2\epsilon_0}\]Which you should notice is uniform throughout space.

Looking for something else?

Not the answer you are looking for? Search for more explanations.