anonymous
  • anonymous
I am so desperate, please help! i have to factor this equation. 21r^2 - rs - 2s^2 As well as solve this one in any way: x^4-21x^2-100=0 Please! The questions are due in 10-15 minutes!
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
(3r-s) (7r+2s) for the first one. (x-5) (x+5) (x^2+4) = 0 x = 5 and x = -5 for the second one. :)
anonymous
  • anonymous
tlau, how did you get the answer?
anonymous
  • anonymous
Factor by inspection. Valid method.

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

jhonyy9
  • jhonyy9
x^4 -21x^2 -100 =0 note x^2=y so than y^2 -21y -100=0 y_1,_2=(21+/- sqrt(441+400))/2=(21+/- sqrt(841))/2 =
anonymous
  • anonymous
wouldn't the answer to the second one also be -4 as well?
anonymous
  • anonymous
You can't square root a negative number. Have you done imaginary numbers?
anonymous
  • anonymous
x^2 = -4 No real number x can be squared to get -4. Any number squared positive or negative is positive.
anonymous
  • anonymous
I did 2 years ago. i'm having to relearn everything as I am starting pre-cal, but now I understand. Thank you very much!
anonymous
  • anonymous
No problem. :D

Looking for something else?

Not the answer you are looking for? Search for more explanations.