anonymous 4 years ago The filament of a light bulb has a temperature of 2580 degrees C and radiates 600 Watts of power at room temperature of 20 degrees C. the emissivity of filament is 0.36. Whats the surface area of the filament? I have it narrowed down to either 0.44 cm^2 or 0.144 cm^2. I can't seem to solve correctly. Please help.

Let's treat it as a blackbody. $P = \epsilon \sigma A_s T^4$