y varies inversely as three times x. When x = 3, y = 4. What is the value of x when y = 2? can someone help me solve?

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y varies inversely as three times x. When x = 3, y = 4. What is the value of x when y = 2? can someone help me solve?

Mathematics
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Diya! Diya!
y varies inversely as three times x \[y=k \times \frac{1}{3x}\] \[4=k \times \frac{1}{3*3}=\frac{k}{9}\]\[4= \frac{k}{9} \ \ or \ \ k= 9*4=36\]\[k=36\] \[ Now\ for \ y=2\] \[2= k \times \frac{1}{3x}= \frac{k}{3x}\]\[2= \frac{k}{3x}=\frac{36}{3x}\]\[2*3x=36 \]\[6x=36\]\[x=\frac{36}{6} =6\]\[x=6\]
varies "inversely". Sometimes I post too quickly

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This is known as inverse proportion :)
Diya deserves the medal, not me, lol
Thanks (:

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