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kiss69fist23
Group Title
2. (2x2 – 23x + 63) ÷ (x – 7) use synthetic division. Show work for full credit.
 2 years ago
 2 years ago
kiss69fist23 Group Title
2. (2x2 – 23x + 63) ÷ (x – 7) use synthetic division. Show work for full credit.
 2 years ago
 2 years ago

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ash2326 Group TitleBest ResponseYou've already chosen the best response.3
(2x^223x+63)/ x7 7 2 23 63 14 63 2 9 0 so (2x^223x+63)/(x7)= 2x9
 2 years ago

kiss69fist23 Group TitleBest ResponseYou've already chosen the best response.0
thank u do u think u cud help me with 2 more?
 2 years ago

ash2326 Group TitleBest ResponseYou've already chosen the best response.3
yeah post them
 2 years ago

kiss69fist23 Group TitleBest ResponseYou've already chosen the best response.0
3. Let f(x) = 4x3 + 7x2 – 13x – 3 and g(x) = x + 3. Find
 2 years ago

kiss69fist23 Group TitleBest ResponseYou've already chosen the best response.0
find f(x)/g(x)
 2 years ago

ash2326 Group TitleBest ResponseYou've already chosen the best response.3
(4x^3+7x^213x3)/(x+3) 3  4 7 13 3 12 15 6 4 5 2 9 so we'll get (4x^25x+2)+ 9/(x+3)
 2 years ago

kiss69fist23 Group TitleBest ResponseYou've already chosen the best response.0
4. Let f(x) = 3x3 – 4x – 1 and g(x) = x + 1. find f(x)/g(x)
 2 years ago

ash2326 Group TitleBest ResponseYou've already chosen the best response.3
(3x^34x1)/(x+1) 1  3 0 4 1 3 +3 1 3 3 1 0 so f(x)/g(x)= 3x^23x1
 2 years ago

kiss69fist23 Group TitleBest ResponseYou've already chosen the best response.0
thank u so much ash
 2 years ago

ricky10messi10 Group TitleBest ResponseYou've already chosen the best response.1
ash you think you can help help me with the same type of exercice?
 2 years ago

ash2326 Group TitleBest ResponseYou've already chosen the best response.3
yeah post it as a new question. I'll help you:)
 2 years ago

ricky10messi10 Group TitleBest ResponseYou've already chosen the best response.1
Let f(x) = x4 – 8x3 + 16x2 – 19 and g(x) = x – 5. Find f(x)/g(x)
 2 years ago

ash2326 Group TitleBest ResponseYou've already chosen the best response.3
@ricky10messi10 please post it as a new question:)
 2 years ago
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