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anonymous

  • 4 years ago

Use elimination to solve the system of equations. Find ordered pairs. { 5x-3y=42 8x+5y=28

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  1. Mertsj
    • 4 years ago
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    Multiply the top equation by 5 Multiply the second equation by 3 Add the two equations.

  2. Mertsj
    • 4 years ago
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    25x-15y=210 24x+15y= 84 49x = 294 Now divide both sides by 49

  3. Mertsj
    • 4 years ago
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    What does x = ?

  4. anonymous
    • 4 years ago
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    x=6 right?

  5. Mertsj
    • 4 years ago
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    yes. Now find y

  6. anonymous
    • 4 years ago
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    how do i find y?

  7. Mertsj
    • 4 years ago
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    Replace x with 6 in any equation that has both an x and a y and solve that equation for y

  8. anonymous
    • 4 years ago
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    so like 5x-3(6)=42?

  9. Mertsj
    • 4 years ago
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    I believe you said that x = 6. So why did you replace y with 6 if it is x that is equal to 6?

  10. anonymous
    • 4 years ago
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    oh! so it would be 5(6)-3=42 i don't understand how to do these problems with elimination, I only know how to do them as substitution.

  11. Mertsj
    • 4 years ago
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    What happened to the y?

  12. Mertsj
    • 4 years ago
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    |dw:1327614823096:dw|

  13. Mertsj
    • 4 years ago
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    Put the 6 where the x was and solve.

  14. anonymous
    • 4 years ago
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    so 30-3y=42 and i miss the 30 from 42 right?

  15. anonymous
    • 4 years ago
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    minus*

  16. Mertsj
    • 4 years ago
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    Subtract 30 from both sides.

  17. anonymous
    • 4 years ago
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    y=4 right?

  18. Mertsj
    • 4 years ago
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    |dw:1327615016204:dw|

  19. Mertsj
    • 4 years ago
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    Divide both sides by -3

  20. anonymous
    • 4 years ago
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    y=-4

  21. Mertsj
    • 4 years ago
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    Yes

  22. Mertsj
    • 4 years ago
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    |dw:1327615140320:dw|

  23. anonymous
    • 4 years ago
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    thank you so much, means alot ^.^ <3

  24. Mertsj
    • 4 years ago
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    yw

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