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anonymous
 4 years ago
They want you to find the average velocity of a car that goes 160 miles north and 120 miles east. they do D = \[\sqrt{(160^2 + 120^2 }\] = 200 miles. Then they do tan^1 120/160 = 36.87, then 90  36.87 = 53.13. WHY do they choose the "90"? because they have chosen different numbers in different problems...
anonymous
 4 years ago
They want you to find the average velocity of a car that goes 160 miles north and 120 miles east. they do D = \[\sqrt{(160^2 + 120^2 }\] = 200 miles. Then they do tan^1 120/160 = 36.87, then 90  36.87 = 53.13. WHY do they choose the "90"? because they have chosen different numbers in different problems...

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amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0velocity is a scalar, not a vector; so directions mean nothing

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0spose we have an interval from [a,b] such that we know the speed at a; f(a). and we know the speed at b; f(b) the average velocity is then just: f(b)f(a)  ba

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0the 90 here would refer to the right angle formed by turning; the other part is the angle of the tangent of the 2 distances; but i got no idea how that relates to avg. velocity ...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0but in other similar problems, they use numbers like 180, and sometimes that add instead of subtracting...
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