waheguru
  • waheguru
Simplaify This 2x^-4y^-3(7x^3y^-2) PLEASE HELP ME
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
waheguru
  • waheguru
I dont understnad how???
anonymous
  • anonymous
|dw:1327615451961:dw|
anonymous
  • anonymous
a negative index = 1 / positive eg x^-2 = 1/x^2

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More answers

anonymous
  • anonymous
the answer can also be written as 14x^-1 y^-5 ( x^-1 = 1/x)
waheguru
  • waheguru
I still doont understanr
anonymous
  • anonymous
hmm - my time is limited at moment - try the khanacademy site wahe - its got a good reputation
waheguru
  • waheguru
why is the 14 positive its -2 x 7 = -14
JamesJ
  • JamesJ
\[ 2x^{-4}y^{-3}(7x^3y^{-2}) \] this is your expression?
waheguru
  • waheguru
the 7 is negavive
JamesJ
  • JamesJ
\[ 2x^{-4}y^{-3}(-7x^3y^{-2}) \] is this it?
waheguru
  • waheguru
can u help me do this one \[4a^7b^5m^10(ten) (8a^9-b^-5m^2)+4a^7m^12/(2a^3bm^2)^5\]
JamesJ
  • JamesJ
wait. Do you have the answer to your first question or not?
waheguru
  • waheguru
yea i just forgot to put the - sigh but i dont get the way jimmy drew it why was the 14 over the other things|dw:1327617362311:dw|
JamesJ
  • JamesJ
Let's try it one more time. Your question then is: Simply this expression \[ 2x^{-4}y^{-3}(7x^3y^{-2}) \] correct?
waheguru
  • waheguru
the 2 is negative ---the first one
waheguru
  • waheguru
What do we do now?
JamesJ
  • JamesJ
So it's this: \[ -2x^{-4}y^{-3}(7x^3y^{-2}) \] yes or no?
waheguru
  • waheguru
yes
JamesJ
  • JamesJ
Right. First of all then, do you agree by the commutative property of multiplication, that we can reorder all of the terms and that \[ -2x^{-4}y^{-3}(7x^3y^{-2}) = (-2)7.x^{-4}x^3.y^{-3}y^{-2} \]
waheguru
  • waheguru
Yes
JamesJ
  • JamesJ
Good. Now we need to simplify each set of terms appropriately. (-2)7 = -14 that's straight forward I hope. What about \[ x^{-4}x^3 \] what's that equal to?
waheguru
  • waheguru
x\[x-1???\]
waheguru
  • waheguru
x^-1
JamesJ
  • JamesJ
yes. And \[ y^{-3}y^{-2} \] is equal to what?
waheguru
  • waheguru
y^-5
JamesJ
  • JamesJ
Yes, hence the answer is \[-14x^{-1}y^{-5} \] which we can also write as \[ \frac{-14}{xy^5} \] that make sense?
waheguru
  • waheguru
I dont get the bottom part
JamesJ
  • JamesJ
By definition \[ x^{-1} \] means and is equal to \[ \frac{1}{x} \]
waheguru
  • waheguru
Oh
JamesJ
  • JamesJ
Therefore also \[ y^{-5} = (y^5)^{-1} = \frac{1}{y^5} \]
waheguru
  • waheguru
SO if it has a power of -2 then the numerator is also 2???
JamesJ
  • JamesJ
in the denominator, yes. For instance \[ 3^{-2} = \frac{1}{3^2} \] That makes good sense because, for example it makes this consistent: \[ 3 = 3^1 \] \[= 3^{3-2} \] \[ = 3^3.3^{-2} \] \[ = 3^3 \frac{1}{3^2} \] \[= 27 \frac{1}{9} \]
waheguru
  • waheguru
k
JamesJ
  • JamesJ
that last expression is 27 times 1/9 which is of course equal to 3.
JamesJ
  • JamesJ
Therefore \[ -14x^{-1}y^{-5} = - \frac{14}{xy^5} \]
waheguru
  • waheguru
Thankyou spoooooo much
waheguru
  • waheguru
4a7b5m10(ten)(8a9−b−5m2)+4a7m12/(2a3bm2)5 can u help me with tis one
waheguru
  • waheguru
\[4a7b5m10(ten)(8a9−b−5m2)+4a7m12/(2a3bm2)5\]
JamesJ
  • JamesJ
ok. good luck with your next one. Work it out patiently. Check it. Do it again. Iron out the errors. See if you can't figure it out. What's you've written is unreadable to me.
waheguru
  • waheguru
oh ill write it again
waheguru
  • waheguru
\[4a^7b^5m^10(ten)(8a^9-b^-5m^2)+4a^7m^12)))divide by (2a^3bm^2)\]
JamesJ
  • JamesJ
To get more than one thing in the exponent, use curly brackets. For example x^{10} \[ x^{10} \] To write a fraction, use \frac{a}{b} \[ \frac{a}{b} \]

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