anonymous
  • anonymous
please help on this math question !
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
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anonymous
  • anonymous
Question number 6 confuses me
anonymous
  • anonymous
http://www.haeseandharris.co.nz/nz/samples/nz11_12.pdf can you also help me on question 2 page 214. the website has the textbook with the picture

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anonymous
  • anonymous
point (3,a) means a = y coordinate at this point so you get a right angled triangle as in drawing:
anonymous
  • anonymous
sorry i meant page number 327
anonymous
  • anonymous
how would i solve for it?
anonymous
  • anonymous
|dw:1327617711449:dw|
anonymous
  • anonymous
by pythagoras a^2 = 5^2 - 3^2 = 16 so a = 4
ksaimouli
  • ksaimouli
jimmrey after u are done with this question help me
anonymous
  • anonymous
second part of q 6: gradient of AP = 4 / (3--5) = 4/8 = 1/2 ..... BP = 4 / (3-5) = -2
anonymous
  • anonymous
i have a question also from the website
anonymous
  • anonymous
http://www.haeseandharris.co.nz/nz/samples/nz11_12.pdf page 327 question number 2a
anonymous
  • anonymous
and 2c
anonymous
  • anonymous
6 c : - ANGLE APB = right angle because gradient of BP * AP = -1
anonymous
  • anonymous
2a average speed = distance/time 920 / 11 = 83.6
anonymous
  • anonymous
oh alright how about question 3
anonymous
  • anonymous
3c part ii
anonymous
  • anonymous
and 2c
anonymous
  • anonymous
2c greatest average speed is where the graph is steepest can u identify this?
anonymous
  • anonymous
CD
anonymous
  • anonymous
no - take a closer look - its BC
anonymous
  • anonymous
how so?
anonymous
  • anonymous
right?
anonymous
  • anonymous
just look at it -the line joining B and C is steeper than AB or CD or OA
anonymous
  • anonymous
ohh alright got it.
anonymous
  • anonymous
how's the weather in new zealand?
anonymous
  • anonymous
summer is there now right

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