waheguru
  • waheguru
Solve THis Using Exponent laws (8^2)^6 PLEASE HELP ME I REALLY NEEDE HELP FAST
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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saifoo.khan
  • saifoo.khan
\[\Huge 8^{2 \times 6}\]
waheguru
  • waheguru
but doesnt the 8 also get timesde by the six
JamesJ
  • JamesJ
\[ (8^2)^6 = 8^2 . 8^2 . 8^2 . 8^2 . 8^2 . 8^2 \ \text{ (six times) } \] \[ = 8^{2+2+2+2+2+2} \] \[ = 8^{2 \times 6} \] \[ = 8^{12} \]

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waheguru
  • waheguru
so 8x6 = 48^12
JamesJ
  • JamesJ
what? Where did that come from?
waheguru
  • waheguru
doesnt the 8 also get multiplyed by 8 or does it stay the same
JamesJ
  • JamesJ
By definition \( 8^{12} \) means 8 multiplied by itself 12 times \[ 8^{12} = 8 \times 8 \times 8 \times 8 \times 8 \times 8 \times 8 \times 8 \times 8 \times 8 \times 8 \times 8 \] Does that answer your question?
waheguru
  • waheguru
ohhhhhhhhhhhh
JamesJ
  • JamesJ
In the same way, \( (8^2)^6 \) means \(8^2 \) multiplied by itself 6 times: \[ (8^2)^6 = (8^2) \times (8^2) \times (8^2) \times (8^2) \times (8^2) \times (8^2) \]
JamesJ
  • JamesJ
That is why the general law is \[ (x^a)^b = x^{ab} \] For your problem then, you can see that we use that law to immediately conclude that \[ (8^2)^6 = 8^{12} \] But you also see from above why that law makes sense and why in this particular case, the result is indeed true.

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