anonymous
  • anonymous
From my previous question : At the moment the train’s speed is 45 km/h, what is the magnitude of the total accelera- tion? Answer in units of m/s2
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
First convert 45 km/hr
anonymous
  • anonymous
12.5 m/s
anonymous
  • anonymous
heres where` the r comes from?? v^2/r

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anonymous
  • anonymous
.959
anonymous
  • anonymous
It doesn't matter what the speed is. The earlier prompt says "slows down at a constant rate" which means the train experiences constant acceleration.
anonymous
  • anonymous
which is?
anonymous
  • anonymous
can you explain this further.
anonymous
  • anonymous
You're right. I overlooked the circular part. \[a = {v^2 \over r}\]
anonymous
  • anonymous
But that is only the centripetal component, there is still the tangential. We are asked for the total magnitude. \[a = \sqrt{\left(v^2 \over 2 \right)^2 + a_t^2}\]where \(a_t\) is the acceleration value you found in the other question.

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