From my previous question : At the moment the train’s speed is 45 km/h, what is the magnitude of the total accelera- tion? Answer in units of m/s2

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From my previous question : At the moment the train’s speed is 45 km/h, what is the magnitude of the total accelera- tion? Answer in units of m/s2

Physics
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First convert 45 km/hr
12.5 m/s
heres where` the r comes from?? v^2/r

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Other answers:

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It doesn't matter what the speed is. The earlier prompt says "slows down at a constant rate" which means the train experiences constant acceleration.
which is?
can you explain this further.
You're right. I overlooked the circular part. \[a = {v^2 \over r}\]
But that is only the centripetal component, there is still the tangential. We are asked for the total magnitude. \[a = \sqrt{\left(v^2 \over 2 \right)^2 + a_t^2}\]where \(a_t\) is the acceleration value you found in the other question.

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