## anonymous 4 years ago Evaluate the definite integral:

1. anonymous

$\int\limits_{4}^{7}t^3\ln(2t)dt$

2. anonymous

If I did integration by parts would the 4 and 7 be in the integral left over?

3. Mertsj

Wolf says 1316.95

4. anonymous

Ok.... how did you get that?

5. Mertsj

1/16t^4(4log(2t)-1)

6. TuringTest

integration by parts$u=\ln(2t)$$dv=t^3$$\int t^3\ln(2t)dt=\frac1 4t^4\ln(2t)-\frac1 4\int t^3dt=\frac1 4t^4\ln(2t)-\frac{1}{16}t^4$$=\frac{1}{16}t^4(4\ln(2t)-1)$evaluate from 4 to 7 forgot parentheses earlier