anonymous
  • anonymous
An airplane flies at airspeed (speed relative to the air) 187 km/h. The pilot wishes to fly due West but there is a 57.7 km/h wind blowing in from North to South. In what direction should the pilot head the plane? Answer in units of  (north of West)
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
What would be the ground speed of the plane (its speed relative to the ground)? Answer in units of km/h
anonymous
  • anonymous
\[v_{w} = (57.7km/hr)\]\[v_{t} = (187km/hr)\] \[v_{a} = v_{t} cos (theta)\] \[v_{w} = v_{t} sin (theta)\]
anonymous
  • anonymous
It's just a 187, 57.5 right triangle|dw:1327639751779:dw| Your new \[\theta\] is just 57.5/187sin^-1\[\theta\] =17.9 degrees above due west (17.9 degrees west-northwest)

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anonymous
  • anonymous
(PS, I can't read the units you require)
anonymous
  • anonymous
Ground speed is \[\sqrt{187^{2}-57.5^{2}}\] = 177.94 kmh

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