## anonymous 4 years ago An airplane flies at airspeed (speed relative to the air) 187 km/h. The pilot wishes to fly due West but there is a 57.7 km/h wind blowing in from North to South. In what direction should the pilot head the plane? Answer in units of (north of West)

1. anonymous

What would be the ground speed of the plane (its speed relative to the ground)? Answer in units of km/h

2. anonymous

$v_{w} = (57.7km/hr)$$v_{t} = (187km/hr)$ $v_{a} = v_{t} cos (theta)$ $v_{w} = v_{t} sin (theta)$

3. anonymous

It's just a 187, 57.5 right triangle|dw:1327639751779:dw| Your new $\theta$ is just 57.5/187sin^-1$\theta$ =17.9 degrees above due west (17.9 degrees west-northwest)

4. anonymous

(PS, I can't read the units you require)

5. anonymous

Ground speed is $\sqrt{187^{2}-57.5^{2}}$ = 177.94 kmh