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anonymous
 4 years ago
So, I had this question on my Calculus 2 test a little bit ago and I could not for the life of me figure out how to solve this. integrate (absolute value of x tanx)/(1  3x^2 + x^8) from .5 to .5
anonymous
 4 years ago
So, I had this question on my Calculus 2 test a little bit ago and I could not for the life of me figure out how to solve this. integrate (absolute value of x tanx)/(1  3x^2 + x^8) from .5 to .5

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Actually I had to prove that it equals zero. \[\int\limits_{.5}^{.5}(\left x \righttanx)/(13x^2 +x^8)=0\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I talked to a friend that said they logically deduced because the top is odd and the bottom is even...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0that is, for the integrand, is \[f(x)=f(x)\]? if so, then the integral has to equal zero because \[\int_{a}^af(x)dx=0\] if f is odd

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0heck no. tangent is odd, not even

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0denominator is even, x is even, but tangent is odd, so the whole thing is odd

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0The function is odd as everything except for tanx is even.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Ahhhh, so all I had to do was to see if it was odd? Goodness, I was trying to some how separate it the denominator to get tan^1. Thank you for your help!!!!
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