anonymous
  • anonymous
Ionic Equations. Na2CO3+AgNO3 --> NaNO3 + Ag2Co3 B: Separate Aqueous solutions, remove spectator ions. C: Net Ionic Equation.
Chemistry
  • Stacey Warren - Expert brainly.com
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
For B, I got 2Na + CO3(2-) +AG(+) + NO3(-) -->Na(+) + NO3(-) + Ag2CO3 C was CO3(2-) +Ag(+) --> Ag2CO3. Do you know if these are right?
Rogue
  • Rogue
Silver carbonate is your insoluble precipitate.\[2Na _{}^{+} + CO _{3}^{2-} + 2Ag _{}^{+} + 2NO _{3}^{-} \rightarrow 2Na _{}^{+} + 2NO _{3}^{-} + Ag _{2}^{}CO _{3}^{} (s)\] Cancel out the spectator ions \[CO _{3}^{2-} + 2Ag _{}^{+} \rightarrow Ag _{2}^{}CO _{3}^{} (s)\]
anonymous
  • anonymous
Why does the Ag on the left have a two in front of it? I noticed this in class, but I could never figure out why.

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Rogue
  • Rogue
So the equation could be balanced, in your equation the # of Ag's on the reactant side does not equal the product side.
anonymous
  • anonymous
I get it. In my class, we do the balancing at the end, during the NET phase. Our teacher saw no reason to balance ahead of time, if some may just be canceled out as spectator ions.
anonymous
  • anonymous
Thanks for the help. Up for some more? I've got seven left. Seven very painful, very chemical, very annoying problems.
Rogue
  • Rogue
Sure, but I won't be solving them, I'll tell you what to do if you get stuck :P
anonymous
  • anonymous
CURSES. My ultimate plan, foiled. You and your stupid dog. The next one I have is Pb(NO3)2 +Na2CO3.
Rogue
  • Rogue
Its pretty much like the last one, but your insoluble precipitate is Phosphorous Carbonate this time.
Rogue
  • Rogue
Oops, lead carbonate
anonymous
  • anonymous
Roger. Give me some time. Like.... an hour. Chemistry is my hardest subject.
anonymous
  • anonymous
ಠ_ಠ
Rogue
  • Rogue
Are you take college chemistry or AP chem in high school?
anonymous
  • anonymous
Chem in high school. It's a cool class and the teacher is awesome, but its so hard. DX Our teacher likes setting things on fire. :)
Rogue
  • Rogue
Sounds fun, last year for ap chem, we had the boring teacher :(
anonymous
  • anonymous
Ouch. I'd hate that. Our teacher makes it enjoyable. Mostly because she acquaints everything with a Metaphor. One of the most memorable ones was selling and buying babies, as electrons.
anonymous
  • anonymous
Wait a minute. How did you get Phosphorous Carbonate? My results were PbCO3 + NaNO3 Did you mean Lead Carbonate?
anonymous
  • anonymous
Or lead something?
anonymous
  • anonymous
*DERP* Just read below it.
anonymous
  • anonymous
K. Results were Pb(NO3)2 + Na2CO3 --> PbCO3 + Na(NO3)
anonymous
  • anonymous
The precipitate is confusing me most. I don't know if I got it right. o.o
Rogue
  • Rogue
Yeah, that seems right, then just separate them into the ions and cancel. The precipitate is the compound that remains a solid dissolved in the aqueous solution; it does not ionize.
anonymous
  • anonymous
Got it. Step A is the hardest to me. Separating & finding NET are much easier. :)
anonymous
  • anonymous
By the way - What's the charge on lead? It's between the negatives and the positives. Confused.
Rogue
  • Rogue
2+ in this situation.
anonymous
  • anonymous
Thank you. I knew it was either 2+ or 4+.
anonymous
  • anonymous
I've got it all set out, what would it be as Balanced? Mine reads: 2 (NO3)2 + Na2 --> 2 Na(NO3) I'm just wondering if my balancing at the end is interfering with anything.
Rogue
  • Rogue
:O Na(NO3) ? thats a spectator.
Rogue
  • Rogue
Pb(NO3)2 + Na2CO3 --> PbCO3 + Na(NO3) Pb2+ + CO3 2- --> PbCO3
anonymous
  • anonymous
I SEE IT. I MESSED UP. I switched the Na(NO3) and the Lead Carbonate. :D At least it was minor.
anonymous
  • anonymous
Mkay. The adjustments made me right. Thanks for that. ಠ_ಠ
anonymous
  • anonymous
The next one is Pb(NO3)2 + Na3PO4 --> PbPO4 + Na(NO3)2. Is that right for the first step?
Rogue
  • Rogue
Your products don't have the right formulas. Lead phosphate is Pb3PO4. Sodium nitrate is NaNO3.
anonymous
  • anonymous
Why does the 2 after Sodium Nitrate go away? I see how I messed up the other one.
anonymous
  • anonymous
NEVERMIND. I see it. Thanks again. :)
anonymous
  • anonymous
:o Is the charge on lead still 2+, or 4+ this time? ;o
anonymous
  • anonymous
ಠ_ಠ Stupid question. Nevermind.
Rogue
  • Rogue
Look at the reactant, Pb(NO3)2. When criss crossed charge is +2.
anonymous
  • anonymous
:) I noticed. Thank you~ :D I need to look more before asking questions. :<
anonymous
  • anonymous
Which one was the precip? :O Lead Phosphate?
Rogue
  • Rogue
Mhm. Use page 2 on this PDF to determine which one is the precipitate. The insoluble compounds are the precipitates. http://www.p12.nysed.gov/apda/reftable/chemistry-rt/chemrt-2011.pdf
anonymous
  • anonymous
:O Thank you. I feel comfortable with these enough to try them on my own. You've been a great help. :D Thanks~!
Rogue
  • Rogue
Alright, no problem, good luck :)

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