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anonymous
 4 years ago
log base 2 fifth root of 32 ?!?!?!?!?!??!?!?!?!!?!??! PLEASE HELP
anonymous
 4 years ago
log base 2 fifth root of 32 ?!?!?!?!?!??!?!?!?!!?!??! PLEASE HELP

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Xishem
 4 years ago
Best ResponseYou've already chosen the best response.0\[\log_{2} \sqrt[5]{32}=\log_{2}2=1\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0how did you get log base 2 then 2?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the fifth root of 32 is 2, because \[2^5=32\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0then shouldn't the answer be five ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so your job is to find \[\log_2(2)\] which asks the question, "what power do you raise the number "2" to to get an answer of 2?" and the answer is clearly 1

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\log_2(2^5)=5\] yes

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0but you have \[\log_2(2)\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0if your question was \[\log_2(2^5)\] the answer would certainly be 5 correct?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i.e. \[\log_2(32)=5\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0wait one sec let me soak this in

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so you're telling me that 2^5 does not equal fifth root of 32?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yes i am. 2^5 = 32 not the fifth root of 32

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so what is it? and how would u find what it is ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i want to know the fifth rote of 32

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0but since 2^5 = 32 then we know that \[\sqrt[5]{32}=2\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you can think of it that way, yes

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0im not understanding what you're telling me

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0which means \[(32)^{\frac{1}{5}}=(2^5)^{\frac{1}{5}}=2^1=2\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0in english: two the the fifth power is 32, therefore the fifth root of 32 is 2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i think i understand that. thank you very much. can you help me with a few more?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[3 \log _{7} \sqrt[6]{49}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok lets do this the easy way. first of all \[\log(x^n)=n\log(x)\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yep. i understand tha :  )

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0and we can rewrite \[\sqrt[6]{49}\] as \[49^{\frac{1}{6}}\] yes?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ummm im kind of confused on those

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0is that just a general rule ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you need to understand exponential notation for logs, because logs are exponents.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yes for example \[\sqrt{x}=x^{\frac{1}{2}}\] \[\sqrt[3]{x}=x^{\frac{1}{3}}\] etc

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0and in general \[\sqrt[n]{x}=x^{\frac{1}{n}}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0okay awesome. just wrote that on my rules sheet XD

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so we start with \[3\log_7(49^{\frac{1}{6}})\] and then bring the 1/6 right out front as a multiplier (coefficient)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\frac{1}{6}\times 3\log_7(49)\] \[\frac{1}{2}\log_7(49)\] and idea what to do next?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i really have no idea :(

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0how can you write 49 with an exponent?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0what would u do if you have a number in front of the log? like the 1/2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0hold on, lets just take care of the 49 first. we can do this problem a different way second

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0we would write \[49=7^2\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0and then you have \[\frac{1}{2}\log_77^2)\] which should be easy now

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0how would we incorporate the 1/2?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0since \[\log_b(b^n)=n\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0we leave it for a moment. the one half out front is just a number, let it sit there

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0we get \[\frac{1}{2}\log_7(7^2)=\frac{1}{2}\times 2\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the answer to \[\log_7(7^2)=2\] and then \[\frac{1}{2}\times 2=1\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh okay!!!!! wow i get that!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0if you like we can do this problem a different way, but maybe one way is enough, you tell me

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i like this way. do u mind helping me with more?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[50 \log 5 \sqrt{125} \]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.05 ^ x = square route 125 ^ 50?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh yikes leave the 50 out front!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i mean you are right, but leave it there to make your life easier. think of how to write 125 as a number raised to a power

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0okay. lol so i have 50 log base 5^x = 5^ 3

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i believe that is wrong

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0close, you just forget the square root

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0but i don't have the square route anymore i got it al out of the square rote

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[125=5^3\] and so \[\sqrt{125}=5^{\frac{3}{2}}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i dont understand that

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0just a moment ago we found out that \[\sqrt{x}=x^{\frac{1}{2}}\] right?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\sqrt{125}=125^{\frac{1}{2}}=(5^3)^{\frac{1}{2}}=5^{\frac{3}{2}}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yes. oh okay i understand

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so then what would we have

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so now we have \[50\log_5(5^{\frac{3}{2}})\] \[50\times \frac{3}{2}\] etc

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0as soon as you say \[\log_b(\text{whatever})\] you should think of ways to write "whatever" as a power of b

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0can u give me an example to try?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\log_3(\sqrt[5]{27})\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0can u do one with a number in front of the log

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the number out front does not really make any difference, but if you like i can write \[10\log_3(\sqrt[5]{27})\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0okay let me get my paper lol

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0really? i got it right?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0don't be so shocked, you will get the hang of it

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0can u help me with more? lol

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0after a couple practice problems you will think "not much to this"

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok we can do another before i go

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\log _{3} 4  1/2 \log _{3} (6x5)\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0holy moly what are the instruction, write as a single log?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0lol i have no idea what to do at all

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0first you need to make sure what the instructions are. what does it say before the problem?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0all it says is : solve

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0maybe u an help me with a different one instead?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you cannot "solve' because there is not an equation here. maybe it says "write as one log"

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0which we can do if you like

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0sure lets write it as one log

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0by what we know before \[n\log(x)=\log(x^n)\] so \[\frac{1}{2}\log(6x5)=\log((6x5)^{\frac{1}{2}})=\log(\sqrt{6x5})\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0also \[\log(a)\log(b)=\log(\frac{a}{b})\] so you can write the whole thing as \[\log_3(\frac{4}{\sqrt{6x5}})\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yes, although the text did not seem to provide a question

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0okay. thank you so so so much for all your help! maybe i will pass math because of you! :D thanks again and have a wonderful day!!
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