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MSMR
 4 years ago
A number x is 2 more than the product of its reciprocal and its additive inverse. In what interval does the number lie?
MSMR
 4 years ago
A number x is 2 more than the product of its reciprocal and its additive inverse. In what interval does the number lie?

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[x+2=\frac{1}{x}\times (x)\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[x=(x)(\frac{1}{x})+2\]You have it backwards, I believe, satellite.

MSMR
 4 years ago
Best ResponseYou've already chosen the best response.0would the interval be \[2<x \le0\]?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[x=1+2=1\]1 is two more than 1*(1/1).

MSMR
 4 years ago
Best ResponseYou've already chosen the best response.0oh, if satellite had it backwards that would make sense. The interval would have to be \[0<x \le2\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0The number lies in an infinite number of different intervals. \[1290 \le x \le 2\]\[0.99999 \le x \le 4\]The question isn't specific to what interval it wants. Your answer works, though.

MSMR
 4 years ago
Best ResponseYou've already chosen the best response.0it's a multiple choice question so it was the only one that worked. thank you! I'm studying for the AMC 10 and it's not fun. :(
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