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MSMR

  • 4 years ago

A number x is 2 more than the product of its reciprocal and its additive inverse. In what interval does the number lie?

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  1. anonymous
    • 4 years ago
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    \[x+2=\frac{1}{x}\times (-x)\]

  2. anonymous
    • 4 years ago
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    \[x+2=1\] \[x=-1\]

  3. Xishem
    • 4 years ago
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    \[x=(-x)(\frac{1}{x})+2\]You have it backwards, I believe, satellite.

  4. MSMR
    • 4 years ago
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    would the interval be \[-2<x \le0\]?

  5. Xishem
    • 4 years ago
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    \[x=-1+2=1\]1 is two more than -1*(1/1).

  6. MSMR
    • 4 years ago
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    oh, if satellite had it backwards that would make sense. The interval would have to be \[0<x \le2\]

  7. MSMR
    • 4 years ago
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    right?

  8. Xishem
    • 4 years ago
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    The number lies in an infinite number of different intervals. \[-1290 \le x \le 2\]\[0.99999 \le x \le 4\]The question isn't specific to what interval it wants. Your answer works, though.

  9. MSMR
    • 4 years ago
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    it's a multiple choice question so it was the only one that worked. thank you! I'm studying for the AMC 10 and it's not fun. :(

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