anonymous
  • anonymous
fourth root of 128n to the 8th power
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
\[(128n)^2\]
anonymous
  • anonymous
\[^{} \sqrt[4]{128}n ^{8}\] thats the anwser for this question?
anonymous
  • anonymous
um. Well, your wording in the original question is rather ambiguous.

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anonymous
  • anonymous
sorry em the question was to simplify \[\sqrt[4]{128}n ^{8}\]
anonymous
  • anonymous
Ahh
anonymous
  • anonymous
:(
anonymous
  • anonymous
\[2*2^{3/4}*n^8=2\sqrt[4]{8}n^8\]
anonymous
  • anonymous
Or, is the \[n^8\] inside the square root or did you really mean \[\sqrt[4]{128}n^8\]
anonymous
  • anonymous
if it was what would the answer b i left the paper
anonymous
  • anonymous
i think it was inside
anonymous
  • anonymous
ok. Then the answer is \[n^22\sqrt[4]{8}\]
anonymous
  • anonymous
how many more questions would u be willing to do?

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