anonymous 4 years ago fourth root of 128n to the 8th power

1. anonymous

$(128n)^2$

2. anonymous

$^{} \sqrt[4]{128}n ^{8}$ thats the anwser for this question?

3. anonymous

um. Well, your wording in the original question is rather ambiguous.

4. anonymous

sorry em the question was to simplify $\sqrt[4]{128}n ^{8}$

5. anonymous

Ahh

6. anonymous

:(

7. anonymous

$2*2^{3/4}*n^8=2\sqrt[4]{8}n^8$

8. anonymous

Or, is the $n^8$ inside the square root or did you really mean $\sqrt[4]{128}n^8$

9. anonymous

if it was what would the answer b i left the paper

10. anonymous

i think it was inside

11. anonymous

ok. Then the answer is $n^22\sqrt[4]{8}$

12. anonymous

how many more questions would u be willing to do?