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anonymous
 4 years ago
i need help with a few questions simplifing radicals with nth roots. only 10 mins of your time please
anonymous
 4 years ago
i need help with a few questions simplifing radicals with nth roots. only 10 mins of your time please

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok it is \[\sqrt[3]{16}a ^{3}b ^{8} \] all underneath the square root sign

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I cant read the exponents they are too small. could you just type it out for mne please?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0a to the 3rd power and b to the eighth power and its to the cube root

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0is the 16 the only thing under the cube root ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yes besides the a to the third power and b to the eighth

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so the variables are NOT under the root?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0sorry my computer froze

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0So we could take the cube root of 16, but thats an ugly number, and we cant take the square root of a negative number so it has to remain under there. The cube root of a cubed is a. for example cube 2 to get 8, the cube root of 8 is 2. so we take a out from under the radical and we have a * cuberoot(16b^8)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0can u type the answer please using equation symbols

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[a * \sqrt[3]{16b^8}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0can u snwser some more? how many are u willing to do

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0we arent done with the problem yet!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Hmm. maybe we are... Hold on just a sec and let me see if that is simplified. I think it is but I dont want to give you false info, I will re ask the question on here and maybe someone smarter than me will respond.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I was really far off. I'm sorry for even trying to attempt that question without having practiced it in over a year. I hope I didnt confuse you. sorry
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