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anonymous

  • 4 years ago

i need help with a few questions simplifing radicals with nth roots. only 10 mins of your time please

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  1. anonymous
    • 4 years ago
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    question?

  2. anonymous
    • 4 years ago
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    ok it is \[\sqrt[3]{-16}a ^{3}b ^{8} \] all underneath the square root sign

  3. anonymous
    • 4 years ago
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    I cant read the exponents they are too small. could you just type it out for mne please?

  4. anonymous
    • 4 years ago
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    sure

  5. anonymous
    • 4 years ago
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    a to the 3rd power and b to the eighth power and its to the cube root

  6. anonymous
    • 4 years ago
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    alrighty

  7. anonymous
    • 4 years ago
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    is the -16 the only thing under the cube root ?

  8. anonymous
    • 4 years ago
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    yes besides the a to the third power and b to the eighth

  9. anonymous
    • 4 years ago
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    so the variables are NOT under the root?

  10. anonymous
    • 4 years ago
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    they are

  11. anonymous
    • 4 years ago
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    okey dokey

  12. anonymous
    • 4 years ago
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    sorry my computer froze

  13. anonymous
    • 4 years ago
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    So we could take the cube root of -16, but thats an ugly number, and we cant take the square root of a negative number so it has to remain under there. The cube root of a cubed is a. for example cube 2 to get 8, the cube root of 8 is 2. so we take a out from under the radical and we have a * cuberoot(-16b^8)

  14. anonymous
    • 4 years ago
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    good so far?

  15. anonymous
    • 4 years ago
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    can u type the answer please using equation symbols

  16. anonymous
    • 4 years ago
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    \[a * \sqrt[3]{-16b^8}\]

  17. anonymous
    • 4 years ago
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    can u snwser some more? how many are u willing to do

  18. anonymous
    • 4 years ago
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    we arent done with the problem yet!

  19. anonymous
    • 4 years ago
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    oh

  20. anonymous
    • 4 years ago
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    Hmm. maybe we are... Hold on just a sec and let me see if that is simplified. I think it is but I dont want to give you false info, I will re ask the question on here and maybe someone smarter than me will respond.

  21. anonymous
    • 4 years ago
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    I was really far off. I'm sorry for even trying to attempt that question without having practiced it in over a year. I hope I didnt confuse you. sorry

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