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anonymous

  • 4 years ago

CUBEROOT(-16a^3b^8)

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  1. anonymous
    • 4 years ago
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    \[\sqrt[3]{-16a^3b^8}\]

  2. anonymous
    • 4 years ago
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    Is it simplified to a * CUBEROOT(-16b^8) ? or in equation form \[a*\sqrt[3]{-16b^8}\]

  3. Akshay_Budhkar
    • 4 years ago
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    \[2ab^2\sqrt[3]{2b^2}\]

  4. anonymous
    • 4 years ago
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    care to explain?

  5. Akshay_Budhkar
    • 4 years ago
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    i just simplified it further by writing 16 as 2 * 8 ( cube root of 8 is 2) similarly writing b^8 as b^2 *b^6 ( cube root of b^6 is b^2)

  6. Akshay_Budhkar
    • 4 years ago
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    are u still confused?

  7. anonymous
    • 4 years ago
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    lemme think for a second

  8. Akshay_Budhkar
    • 4 years ago
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    sure its easy ..

  9. anonymous
    • 4 years ago
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    that makes me feel better...

  10. anonymous
    • 4 years ago
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    and then you just took the a out right?

  11. anonymous
    • 4 years ago
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    will you give me a practice one to see if i can get it right?

  12. Akshay_Budhkar
    • 4 years ago
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    yes i just took it out right

  13. Akshay_Budhkar
    • 4 years ago
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    ok i will give u a question

  14. Akshay_Budhkar
    • 4 years ago
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    \[\sqrt[3]{48a^6b^5}\]

  15. anonymous
    • 4 years ago
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    4a^2b * cuberoot(3b^2)

  16. Akshay_Budhkar
    • 4 years ago
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    your variables a and b are correct, but there seems to be a problem in your constant.. look again and think with a cool mind

  17. anonymous
    • 4 years ago
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    Oops i see where i messed up

  18. Akshay_Budhkar
    • 4 years ago
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    lol its good to realize your mistakes :)

  19. anonymous
    • 4 years ago
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    very true

  20. Akshay_Budhkar
    • 4 years ago
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    so correct yourself

  21. anonymous
    • 4 years ago
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    2 is the outside coefficient, and 6 is the inside coefficient

  22. Akshay_Budhkar
    • 4 years ago
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    yup correct :D you got it :)

  23. anonymous
    • 4 years ago
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    yay, thanks for your help

  24. Akshay_Budhkar
    • 4 years ago
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    my pleasure :D

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