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UnkleRhaukus

  • 4 years ago

\[(3x-y+1)dx-(6x-2y-3)dy=0\]

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  1. UnkleRhaukus
    • 4 years ago
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    \[{dy \over dx}={3x-y+1 \over 6x-2y-3}\] let \[w= 6x-2y-3\]\[dw=6dx\] \[dy={1 \over 2 }(w+5/w)6dw\]\[y=3 \int(1+5/w)dw\]\[y=3(w+5lnw)+c)\]

  2. UnkleRhaukus
    • 4 years ago
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    is this right?

  3. Akshay_Budhkar
    • 4 years ago
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    u have taken w=6x-2y-3 so if u differentiate shouldnt it be dw=6dx - 2dy?

  4. UnkleRhaukus
    • 4 years ago
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    yeah that was the step that i was having problems with, what am i supposed to do intergrate two regions?

  5. Akshay_Budhkar
    • 4 years ago
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    lemme think i am not getting it.. did u try taking y= vx ? (y/x=v)

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