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anonymous

  • 4 years ago

integral of sec^4 x * cos^2x * tan ^7x dx tired and brain dead someone do it for me plz

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  1. anonymous
    • 4 years ago
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    if you want an answer try http://www.wolframalpha.com/input/?i=sec^4+x+*+cos^2x+*+tan+^7x+dx

  2. anonymous
    • 4 years ago
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    pellet son thats a convenient cheater box u got there

  3. anonymous
    • 4 years ago
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    but you see it is simple answer and that is because \[\sec^4(x)\times \cos^2(x)=\frac{\cos^2(x)}{\cos^4(x)}=\sec^2(x)\]

  4. anonymous
    • 4 years ago
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    so really you just have \[\int\tan^7(x)\sec^2(x)dx\] and a simple u -sub gives it in one step

  5. anonymous
    • 4 years ago
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    oh wow thats embarrassing

  6. anonymous
    • 4 years ago
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    lol

  7. anonymous
    • 4 years ago
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    ok one more

  8. anonymous
    • 4 years ago
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    right circular cylinder is inscribed in a cone with height h and base radius r Find the largest possible volume of such a cylinder

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