## anonymous 4 years ago lim as x approches infinity of 7-x+8x^2/4x^3+2

1. Xishem

$\lim_{x \rightarrow \infty}\frac{8x^2-x+7}{4x^3+2}$Since this is of indeterminate form ∞/∞, you can use L Hopital's rule: $\lim_{x \rightarrow \infty}\frac{16x-1}{12x^2}=\lim_{x \rightarrow \infty}\frac{16}{24x}=0$

2. anonymous

Thanks!

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