## Lukecrayonz 4 years ago Determine how many moles are present in 523.46g of glucse, C6H12O6

1. anonymous

Same way as the last one -> C = 12g/mol, H = 1g/mol, and O = 16g/mol $C_6H_{12}O6 = 180g/mol$ $523.46g * 1 mol/180g = 2.90mol$

2. anonymous

$523.46g(glucose)*\frac{1mol(glucose)}{180.16g(glucose)}=2.9055mol(glucose)$

3. anonymous

lol to 5 sfs :p

4. anonymous

Why not? :D

5. Preetha

How many Sf should there be in this solution?

6. anonymous

I see no reason to have less than 5. If I'm justified keeping that many sf (which you almost never are), I'm definitely going to.