Determine how many moles are present in 523.46g of glucse, C6H12O6

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Determine how many moles are present in 523.46g of glucse, C6H12O6

Chemistry
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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Same way as the last one -> C = 12g/mol, H = 1g/mol, and O = 16g/mol \[C_6H_{12}O6 = 180g/mol\] \[523.46g * 1 mol/180g = 2.90mol\]
\[523.46g(glucose)*\frac{1mol(glucose)}{180.16g(glucose)}=2.9055mol(glucose)\]
lol to 5 sfs :p

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Other answers:

Why not? :D
How many Sf should there be in this solution?
I see no reason to have less than 5. If I'm justified keeping that many sf (which you almost never are), I'm definitely going to.

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