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anonymous
 4 years ago
In Walter Lewin's lecture explaining RL circuits, he says:
"The electric field in the selfinductance is 0 because the selfinductance has no resistance, it's superconducting material."
I understand that the inductor has no resistance, but why does that mean that the electric field is zero here?
Thank you!
anonymous
 4 years ago
In Walter Lewin's lecture explaining RL circuits, he says: "The electric field in the selfinductance is 0 because the selfinductance has no resistance, it's superconducting material." I understand that the inductor has no resistance, but why does that mean that the electric field is zero here? Thank you!

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Via Ohms Law, \[R = \frac{\Delta V}{I} = 0 \rightarrow \Delta V = 0\] The electric field is \[E = \frac{dV}{dx} \] And since the voltage is constant, E is the derivative of a constant, or zero.
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