anonymous
  • anonymous
In Walter Lewin's lecture explaining RL circuits, he says: "The electric field in the self-inductance is 0 because the self-inductance has no resistance, it's super-conducting material." I understand that the inductor has no resistance, but why does that mean that the electric field is zero here? Thank you!
MIT 8.02 Electricity and Magnetism, Spring 2002
katieb
  • katieb
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anonymous
  • anonymous
Via Ohms Law, \[R = \frac{\Delta V}{I} = 0 \rightarrow \Delta V = 0\] The electric field is \[E = -\frac{dV}{dx} \] And since the voltage is constant, E is the derivative of a constant, or zero.
anonymous
  • anonymous
thank you! :)

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