## anonymous 4 years ago In Walter Lewin's lecture explaining RL circuits, he says: "The electric field in the self-inductance is 0 because the self-inductance has no resistance, it's super-conducting material." I understand that the inductor has no resistance, but why does that mean that the electric field is zero here? Thank you!

1. anonymous

Via Ohms Law, $R = \frac{\Delta V}{I} = 0 \rightarrow \Delta V = 0$ The electric field is $E = -\frac{dV}{dx}$ And since the voltage is constant, E is the derivative of a constant, or zero.

2. anonymous

thank you! :)