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anonymous
 4 years ago
Optimization. At 12 noon a ship going due east at 12 knots crosses 10 nautical miles ahead
of a second ship going due north at 16 knots.
a) If s is the number of nautical miles separating the ships, express s in
terms of t (the number of hours after 12 noon).
b) When are the ships closest and what is the least distance between them
anonymous
 4 years ago
Optimization. At 12 noon a ship going due east at 12 knots crosses 10 nautical miles ahead of a second ship going due north at 16 knots. a) If s is the number of nautical miles separating the ships, express s in terms of t (the number of hours after 12 noon). b) When are the ships closest and what is the least distance between them

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the distance would be sqrt( (12t)^2 + (1016t)^2 ) nautical miles differentiate and you would get t = 17/16 hours after 12 or 1 hour 3 minutes 45 seconds after 12 or 1:03:45 P.M.
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