## anonymous 4 years ago How do you solve this inequality? n-5/2<2n-6/3

1. Hunus

is that $\frac{n-5}{2}<\frac{2n-6}{3}$

2. anonymous

yes

3. anonymous

Actually <_

4. anonymous

but I doubt it would make a difference

5. Hunus

$(\frac{n-5}{2})\le(\frac{2n-6}{3})$ $(\frac{n-5}{2})(3)\le(\frac{2n-6}{3})(3)$ $(\frac{n-5}{2})(2)(3)\le(2n-6)(2)$ $(n-5)(3)\le(2n-6)(2)$ $-15\le n-12$ $-3\le n$ $n \ge -3$

6. anonymous

THANK YOU SO MUCH! can you help me with one more?

7. Hunus

Sure :)

8. anonymous

i'll post a question with your name and give another medal to you

9. Hunus

okay :)