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sakigirl

  • 4 years ago

How do you solve this inequality? n-5/2<2n-6/3

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  1. Hunus
    • 4 years ago
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    is that \[\frac{n-5}{2}<\frac{2n-6}{3}\]

  2. sakigirl
    • 4 years ago
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    yes

  3. sakigirl
    • 4 years ago
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    Actually <_

  4. sakigirl
    • 4 years ago
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    but I doubt it would make a difference

  5. Hunus
    • 4 years ago
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    \[(\frac{n-5}{2})\le(\frac{2n-6}{3})\] \[(\frac{n-5}{2})(3)\le(\frac{2n-6}{3})(3)\] \[(\frac{n-5}{2})(2)(3)\le(2n-6)(2)\] \[(n-5)(3)\le(2n-6)(2)\] \[-15\le n-12\] \[ -3\le n\] \[n \ge -3\]

  6. sakigirl
    • 4 years ago
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    THANK YOU SO MUCH! can you help me with one more?

  7. Hunus
    • 4 years ago
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    Sure :)

  8. sakigirl
    • 4 years ago
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    i'll post a question with your name and give another medal to you

  9. Hunus
    • 4 years ago
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    okay :)

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