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anonymous

  • 4 years ago

A steel rivet 1.871cm in diameter is to be placed in a hole 1.869cm in diameter. To what temperature must the rivet be cooled if it is to fit in the hole(at 20 degrees celcius)

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  1. anonymous
    • 4 years ago
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    help :)

  2. anonymous
    • 4 years ago
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    What is the linear coefficient of thermal expansion for steel?

  3. anonymous
    • 4 years ago
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    10.5 x 10 to the -6

  4. anonymous
    • 4 years ago
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    |dw:1327638523463:dw|

  5. anonymous
    • 4 years ago
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    \[{\Delta L \over L_i} = \alpha_L \Delta T\]where L will be the radius.

  6. anonymous
    • 4 years ago
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    can you show the work plz and what you pluged in cuz i got a test tommorow

  7. anonymous
    • 4 years ago
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    \[{(1.869 - 1.871) \over 1.871} = \alpha (T_f - 20)\]

  8. anonymous
    • 4 years ago
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    whats the alpha

  9. anonymous
    • 4 years ago
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    linear coefficient of thermal expansion

  10. anonymous
    • 4 years ago
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    Make sure it has units of m/C. If not, you need to convert the temperature to Kelvin.

  11. anonymous
    • 4 years ago
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    oh ok thank you so much man, you dont mind if you help me out with some more problems

  12. anonymous
    • 4 years ago
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    how?

  13. anonymous
    • 4 years ago
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    Not at all. Post them.

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