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anonymous
 4 years ago
An air bubble at the bottom of a lake 43.5m deep has a volume of 1.00cm/cubed. If the temperature at the bottom is 5.5 degrees celcius and at the top 21.0 degrees celcius, what is the volume of the bubble just before it reaches the surface.
anonymous
 4 years ago
An air bubble at the bottom of a lake 43.5m deep has a volume of 1.00cm/cubed. If the temperature at the bottom is 5.5 degrees celcius and at the top 21.0 degrees celcius, what is the volume of the bubble just before it reaches the surface.

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Are we ignoring pressure effects here? These are more substantial than temperature effects.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0and how do i convert Celsius to kelvin

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Do you have the volumetric coefficient of thermal expansion for air? Otherwise, we will have to use the ideal gas law which requires we make some assumptions.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i think well have to use ideal gas law

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Then pressure is definitely being accounted for. First, let's find the pressure at the bottom of the lake. \[P_b = \rho g h + P_{atm}\]where \(P_{atm} = 101 kPa = 1 atm = 14.7 psi\) Now, from ideal gas law, \[\left [ PV \over n RT \right ]_{bottom} = \left [ PV \over nRT \right ] _{t o p}\]n remains constant so it cancels out. We just calculated the pressure at the bottom, the pressure at the top will be equal to \(P_{atm}\). We know the volume at the bottom and the two temperatures. Leaving the volume at the top the only unknown.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0what do i plug in for pressure at the bottom of the lake

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0can you show me what to plug in

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0You have to solve for it It is\[P_{Bottom} = \rho gh + P_{atm}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0but what do i put in for density

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0and is the g gravity 9.8

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Depends on what units you want. Looks like we are in SI, so density would be 1000 kg/m^3 for water, and g is definitely 9.8.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Indeed. The height of the water column above the bubble.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0p.s. your a genius man

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0what do i put for nRT

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0for R. T must be in kelvin.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0how did you get that?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0The n cancels out. because it does not change.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0help me on the other one
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