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anonymous
 4 years ago
How many solutions exist for the system, x + y = 1 and y = x + 1?
A. no solution
B. one solution
C. infinitely many solutions
I think its C.... am I right?
anonymous
 4 years ago
How many solutions exist for the system, x + y = 1 and y = x + 1? A. no solution B. one solution C. infinitely many solutions I think its C.... am I right?

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0thnk u for ur answer Salv.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0sorry, don't know what happened to my post

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0it's C: if you tried substituting either x=y+1 or y=x+1 into x+y=1 you would find that the variable will cancel leaving you with a consistent equation 1=1. The fact that the variable cancels means that it may be anything. Since this is true for both x and y (which ever substitution you choose to make) then there are infinitely many solutions.
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