## anonymous 4 years ago can anyone help me with this... x^2/3 + 4x^1/3 + 3 = 0 How do I solve this?

1. anonymous

Factorize it as : (x^(1/3)+1) (x^(1/3)+3) = 0

2. campbell_st

well the equation is $\sqrt[3]{x^2} + 4\sqrt[3]{x} + 3 = 0$ use a substitution and let $u = x^ (1/3)$ then the problem is $u^2 + 4u + 3 = 0$ solve for u ((u+1)(u+3)=0 u = -1,-3 then find $x = \sqrt[3]{(-1)}$ and $x = \sqrt[3]{-3}$ are the solutions